# CONVERSION OF VOLUME OF NATURAL GAS TO MASS OF NATURAL GAS

People often ask how do convert a volume (e.g., standard cubic feet) of natural gas to pounds (mass) and pounds of natural gas to volume. Below are some equations to use with a more detailed explanation later in this blog topic.

Conversion of natural gas volume to weight (mass) requires the volume of gas in standard cubic feet and the molecular weight of the natural gas. Below is a sample calculation with equations to use.

 Converting from volume of natural gas to pounds (lbs) of natural gas in SCF Volume of gas: 50,000 standard cubic feet (SCF) at 60°F and 14.7psia Molecular weight (MW) of natural gas: 20 lbs/lb-mole Ideal gas law conversion factor: 379.3 SCF/lb-mole  (see Reference 1) Weight (mass) of natural gas: 2636.4 lbs      (see Equation 1) Weight (mass) of natural gas: 1.32 tons    (see Equation 2) Equations Used: Equation 1:  Weight in lbs of total gas = (SCF)*(1 lb-mole/379.3 SCF)*(MW of gas in lbs/lb-mole) Equation 2:  Weight in tons of total gas = (lbs of natural gas)(1 ton/2000 lbs)

 Converting from pounds (lbs) of natural gas to volume of natural gas in SCF Mass of gas: 10,000 lbs Molecular weight (MW) of natural gas: 20 lbs/lb-mole Ideal gas law conversion factor: 379.3 SCF/lb-mole  (see Reference 1) Volume of natural gas: 189,650 SCF    (see Equation 3) Equation Used: Equation 3:  Vol. total gas in SCF = (lbs natural gas)*(379.3 SCF/lb-mole)÷(MW of gas in lbs/lb-mole)

The ideal gas law conversion factor used above is based on the relationship of 1 lb-mole of an ideal gas occupies approx. 379.3 SCF at standard conditions of 60°F and 14.7psia (see Reference 1). Typically, for air quality regulatory calculations for natural gas and its components, an ideal gas is assumed and compressibility factors (Z-factors) are not used.

Discussion

Oil company field operations and engineering departments think in terms of the volume of gas since the volume produced will be normally be reported as standard cubic feet (SCF) at 60°F and 14.7psia (see Reference 1 below). Air quality regulations customarily express limits based on the mass amount (e.g. pounds or tons) of the gas emitted to the atmosphere.

If you are going to communicate effectively with field operations, then you need to be able to convert between pounds (lbs) of gas (weight) to SCF of gas (volume) and also from SCF to lbs.

Below is some more useful information to help you do the conversions.

Natural Gas Pressure Units

• psia = pounds per square inch absolute
• psig = pounds per square inch gauge; 0 psig = 14.7 psia (most common units for gas pressure in oilfield). If gas units are in psig, then to obtain psia, add 14.7 to the gauge pressure to get the absolute pressure (psia).

Natural Gas Standard Conditions

For oilfield operations, natural gas at standard conditions normally refers to gas volumes measured at:

• 60°F and 14.7 psia

If have 1000 SCF of a natural gas, it is based on the natural gas at standard conditions of 60°F and 14.7 psia – even if the actual temperature and pressure of the gas produced was higher. If you have actual conditions of pressure and temperature, a conversion from actual gas temperature and pressure is needed to convert the gas volume to standard conditions.

Most production reports and gas analyses will already be in SCF so no conversion should be needed.

Conversion of Gas Volume to Standard Conditions

Below is a conversion of actual conditions of 1000 cubic foot of natural gas at 100°F and 100 psig to standard conditions.

V1 = desired value of gas volume at standard conditions of 60°F and 14.7 psia

• P1 = 14.7 psia
• T1 = 60°F
• V2 = 1000 cubic foot (actual)
• P2 = 100 psig (actual)
• T2 = 100°F (actual)

The formula to convert from actual conditions to standard conditions uses the relationship from Boyle’s and Charles’s laws:

Equation 4:  P1*V1÷T1 = P2*V2÷T2

To use Equation 4 above, you must convert the actual pressure (P2) to psia (by adding 14.7 to the psig value) and the actual temperature (T2) to degrees Rankine, °R (by adding 459.67 to the actual temperature in °F).

Equation 5:  Solve for V1 = (P2*V2*T1)÷(P1*T2)

Solving for V1 (standard conditions volume) using Equation 5:

V1 in SCF = [(100 psig + 14.7)*(1000 cubic feet)*(60°F + 459.67)] ÷ [(14.7psia)*(100°F + 459.67)]

V1 = 7,245 SCF

References

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